What are the solutions to the equation t^2-4t=0 ?

The solutions to the equation t^2-4t=0 are t=4,t=0

Find the zeros of t^2-4t=0

The zeros of t^2-4t=0 are t=4,t=0

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t^{2} - 4 t = 0

t = 4, t = 0

Solution steps

t^{2} - 4 t = 0

Solve with the quadratic formula

t_{1, 2} = \frac{- ( - 4 ) \pm ( - 4 ) ^{2} - 4 \cdot 1 \cdot 0}{2 \cdot 1}

(- 4)^{2} - 4 \cdot 1 \cdot 0 = 4

t_{1, 2} = \frac{- ( - 4 ) \pm 4}{2 \cdot 1}

Separate the solutions

t_{1} = \frac{- ( - 4 ) + 4}{2 \cdot 1}, t_{2} = \frac{- ( - 4 ) - 4}{2 \cdot 1}

t = \frac{- ( - 4 ) + 4}{2 \cdot 1} : 4

t = \frac{- ( - 4 ) - 4}{2 \cdot 1} : 0

The solutions to the quadratic equation are:

t = 4, t = 0

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What are the solutions to the equation t^2-4t=0 ?
The solutions to the equation t^2-4t=0 are t=4,t=0
Find the zeros of t^2-4t=0
The zeros of t^2-4t=0 are t=4,t=0