What is (a^3-2a^2)-(3a^2-4a^3) ?

The solution to (a^3-2a^2)-(3a^2-4a^3) is 5a^3-5a^2

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simplify (a^3-2a^2)-(3a^2-4a^3)

simplify

(a^{3} - 2 a^{2}) - (3 a^{2} - 4 a^{3})

5 a^{3} - 5 a^{2}

Solution steps

(a^{3} - 2 a^{2}) - (3 a^{2} - 4 a^{3})

Apply rule:

(a) = a

(a^{3} - 2 a^{2}) = a^{3} - 2 a^{2}

= a^{3} - 2 a^{2} - (3 a^{2} - 4 a^{3})

Apply the distributive law:

- (a - b) = - a + b

- (3 a^{2} - 4 a^{3}) = - 3 a^{2} + 4 a^{3}

= a^{3} - 2 a^{2} - 3 a^{2} + 4 a^{3}

Add similar elements:

- 2 a^{2} - 3 a^{2} = - 5 a^{2}

= a^{3} - 5 a^{2} + 4 a^{3}

Group like terms

= a^{3} + 4 a^{3} - 5 a^{2}

Add similar elements:

a^{3} + 4 a^{3} = 5 a^{3}

= 5 a^{3} - 5 a^{2}

\frac{14}{6}

(- x^{2} + 2 x) - (x^{2} - 2 x)

\frac{ab}{9 a ^{2} - b ^{2}} + \frac{a}{3 a + b}

\frac{4}{- 3}

(p + 5 q)^{2}

What is (a^3-2a^2)-(3a^2-4a^3) ?
The solution to (a^3-2a^2)-(3a^2-4a^3) is 5a^3-5a^2