What are the solutions to the equation 4(x-1)-2x(x+3)=0 ?

The solutions to the equation 4(x-1)-2x(x+3)=0 are x=-1/2-i(sqrt(7))/2 ,x=-1/2+i(sqrt(7))/2

Find the zeros of 4(x-1)-2x(x+3)=0

The zeros of 4(x-1)-2x(x+3)=0 are x=-1/2-i(sqrt(7))/2 ,x=-1/2+i(sqrt(7))/2

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4 (x - 1) - 2 x (x + 3) = 0

x = - \frac{1}{2} - i \frac{7}{2}, x = - \frac{1}{2} + i \frac{7}{2}

Solution steps

4 (x - 1) - 2 x (x + 3) = 0

Expand

4 (x - 1) - 2 x (x + 3) : - 2 x^{2} - 2 x - 4

- 2 x^{2} - 2 x - 4 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 2 ) \pm ( - 2 ) ^{2} - 4 ( - 2 ) ( - 4 )}{2 ( - 2 )}

Simplify

(- 2)^{2} - 4 (- 2) (- 4) : 27 i

x_{1, 2} = \frac{- ( - 2 ) \pm 2 7 i}{2 ( - 2 )}

Separate the solutions

x_{1} = \frac{- ( - 2 ) + 2 7 i}{2 ( - 2 )}, x_{2} = \frac{- ( - 2 ) - 2 7 i}{2 ( - 2 )}

x = \frac{- ( - 2 ) + 2 7 i}{2 ( - 2 )} : - \frac{1}{2} - i \frac{7}{2}

x = \frac{- ( - 2 ) - 2 7 i}{2 ( - 2 )} : - \frac{1}{2} + i \frac{7}{2}

The solutions to the quadratic equation are:

x = - \frac{1}{2} - i \frac{7}{2}, x = - \frac{1}{2} + i \frac{7}{2}

- 16 \cdot 4

(\frac{5}{6})^{4}

3 (2 z - 6 + z) > 63

2 x + 5 \geq 7

- 2 - 2 i

What are the solutions to the equation 4(x-1)-2x(x+3)=0 ?
The solutions to the equation 4(x-1)-2x(x+3)=0 are x=-1/2-i(sqrt(7))/2 ,x=-1/2+i(sqrt(7))/2
Find the zeros of 4(x-1)-2x(x+3)=0
The zeros of 4(x-1)-2x(x+3)=0 are x=-1/2-i(sqrt(7))/2 ,x=-1/2+i(sqrt(7))/2