What is (8x^6y^{-15}z^3)^{2/3}*(49x^{-2}y^8z^2)^{-1/2} ?

The solution to (8x^6y^{-15}z^3)^{2/3}*(49x^{-2}y^8z^2)^{-1/2} is (4x^5z)/(7y^{14)}

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

simplify (8x^6y^{-15}z^3)^{2/3}*(49x^{-2}y^8z^2)^{-1/2}

simplify

(8 x^{6} y^{- 15} z^{3})^{\frac{2}{3}} \cdot (49 x^{- 2} y^{8} z^{2})^{- \frac{1}{2}}

\frac{4 x ^{5} z}{7 y ^{14}}

Solution steps

(8 x^{6} y^{- 15} z^{3})^{\frac{2}{3}} (49 x^{- 2} y^{8} z^{2})^{- \frac{1}{2}}

Simplify

(8 x^{6} y^{- 15} z^{3})^{\frac{2}{3}} : \frac{4 x ^{4} z ^{2}}{y ^{10}}

= \frac{4 x ^{4} z ^{2}}{y ^{10}} (49 x^{- 2} y^{8} z^{2})^{- \frac{1}{2}}

Simplify

(49 x^{- 2} y^{8} z^{2})^{- \frac{1}{2}} : \frac{x}{7 y ^{4} z}

= \frac{4 x ^{4} z ^{2}}{y ^{10}} \cdot \frac{x}{7 y ^{4} z}

Apply the fraction rule:

\frac{a}{b} \cdot \frac{c}{d} = \frac{a \cdot c}{b \cdot d}

= \frac{4 x ^{4} z ^{2} x}{y ^{10} \cdot 7 y ^{4} z}

Simplify

\frac{z ^{2}}{z} : z

= \frac{4 x ^{4} z x}{y ^{10} \cdot 7 y ^{4}}

Simplify

x^{4} x : x^{5}

= \frac{4 x ^{5} z}{y ^{10} \cdot 7 y ^{4}}

Simplify

y^{10} y^{4} : y^{14}

= \frac{4 x ^{5} z}{y ^{14} \cdot 7}

= \frac{4 x ^{5} z}{7 y ^{14}}

(x^{2} + 8 x + 8) + (- 10 x^{2} + 5 x)

\frac{49}{2}

(2 x + 1) (x + 2)

lo g_{0.25} (16)

32 \div 8

What is (8x^6y^{-15}z^3)^{2/3}*(49x^{-2}y^8z^2)^{-1/2} ?
The solution to (8x^6y^{-15}z^3)^{2/3}*(49x^{-2}y^8z^2)^{-1/2} is (4x^5z)/(7y^{14)}