What is (5x+25)/(14)*(7x+7)/(10x+50) ?

The solution to (5x+25)/(14)*(7x+7)/(10x+50) is (x+1)/4

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simplify (5x+25)/(14)*(7x+7)/(10x+50)

simplify

\frac{5 x + 25}{14} \cdot \frac{7 x + 7}{10 x + 50}

\frac{x + 1}{4}

Solution steps

\frac{5 x + 25}{14} \cdot \frac{7 x + 7}{10 x + 50}

Apply the fraction rule:

\frac{a}{b} \cdot \frac{c}{d} = \frac{a \cdot c}{b \cdot d}

= \frac{( 5 x + 25 ) ( 7 x + 7 )}{14 ( 10 x + 50 )}

Factor

7 x + 7 : 7 (x + 1)

= \frac{( 5 x + 25 ) \cdot 7 ( x + 1 )}{14 ( 10 x + 50 )}

Factor the number:

14 = 7 \cdot 2

= \frac{( 5 x + 25 ) \cdot 7 ( x + 1 )}{7 \cdot 2 ( 10 x + 50 )}

Cancel the common factor:

7

= \frac{( 5 x + 25 ) ( x + 1 )}{2 ( 10 x + 50 )}

Factor

5 x + 25 : 5 (x + 5)

= \frac{5 ( x + 5 ) ( x + 1 )}{2 ( 10 x + 50 )}

Factor

10 x + 50 : 10 (x + 5)

= \frac{5 ( x + 5 ) ( x + 1 )}{2 \cdot 10 ( x + 5 )}

Cancel the common factor:

x + 5

= \frac{5 ( x + 1 )}{2 \cdot 10}

Factor the number:

10 = 5 \cdot 2

= \frac{5 ( x + 1 )}{2 \cdot 5 \cdot 2}

Cancel the common factor:

5

= \frac{x + 1}{2 \cdot 2}

Multiply the numbers:

2 \cdot 2 = 4

= \frac{x + 1}{4}

(2 a - 6) (2 a + 4)

lo g_{3} (3^{5})

\frac{6 ^{2} 3}{4}

(x - 4) (3 x^{2} + 4 x - 4)

(3 y^{2} + y^{3} - 5) + (4 y^{2} - 4 y + 2 y^{3} + 8)

What is (5x+25)/(14)*(7x+7)/(10x+50) ?
The solution to (5x+25)/(14)*(7x+7)/(10x+50) is (x+1)/4