What is (e^x-e^{-x})/(e^x+e^{-x)} ?

The solution to (e^x-e^{-x})/(e^x+e^{-x)} is (e^{2x}-1)/(e^{2x)+1}

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simplify (e^x-e^{-x})/(e^x+e^{-x)}

simplify

\frac{e ^{x} - e ^{- x}}{e ^{x} + e ^{- x}}

\frac{e ^{2 x} - 1}{e ^{2 x} + 1}

Solution steps

\frac{e ^{x} - e ^{- x}}{e ^{x} + e ^{- x}}

Factor

e^{x} - e^{- x} : e^{- x} (e^{2 x} - 1)

= \frac{e ^{- x} ( e ^{2 x} - 1 )}{e ^{x} + e ^{- x}}

Factor

e^{x} + e^{- x} : e^{- x} (e^{2 x} + 1)

= \frac{e ^{- x} ( e ^{2 x} - 1 )}{e ^{- x} ( e ^{2 x} + 1 )}

Cancel the common factor:

e^{- x}

= \frac{e ^{2 x} - 1}{e ^{2 x} + 1}

2 \times (- 4)

\frac{3}{4} \div \frac{2}{5}

\frac{8}{9}

\frac{x ^{2} + 2 x - 3}{x + 3}

(x - 6) (x + 1)

What is (e^x-e^{-x})/(e^x+e^{-x)} ?
The solution to (e^x-e^{-x})/(e^x+e^{-x)} is (e^{2x}-1)/(e^{2x)+1}