What are the solutions to the equation 2(7x-2)(2x+7)=0 ?

The solutions to the equation 2(7x-2)(2x+7)=0 are x= 2/7 ,x=-7/2

Find the zeros of 2(7x-2)(2x+7)=0

The zeros of 2(7x-2)(2x+7)=0 are x= 2/7 ,x=-7/2

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2 (7 x - 2) (2 x + 7) = 0

x = \frac{2}{7}, x = - \frac{7}{2}

Solution steps

2 (7 x - 2) (2 x + 7) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

7 x - 2 = 0 or 2 x + 7 = 0

Solve

7 x - 2 = 0 : x = \frac{2}{7}

Solve

2 x + 7 = 0 : x = - \frac{7}{2}

The solutions to the quadratic equation are:

x = \frac{2}{7}, x = - \frac{7}{2}

x^{2} - 24 > 1

2 x + 1 \leq - 2

x^{2} - 3 x - 54

x^{0}

9 a^{2} - 16

What are the solutions to the equation 2(7x-2)(2x+7)=0 ?
The solutions to the equation 2(7x-2)(2x+7)=0 are x= 2/7 ,x=-7/2
Find the zeros of 2(7x-2)(2x+7)=0
The zeros of 2(7x-2)(2x+7)=0 are x= 2/7 ,x=-7/2