What is ((x^3+x^2-10x+8))/((x-2)) ?

The solution to ((x^3+x^2-10x+8))/((x-2)) is (x-1)(x+4)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

simplify ((x^3+x^2-10x+8))/((x-2))

simplify

\frac{( x ^{3} + x ^{2} - 10 x + 8 )}{( x - 2 )}

(x - 1) (x + 4)

Solution steps

\frac{x ^{3} + x ^{2} - 10 x + 8}{x - 2}

Use the rational root theorem

= \frac{( x - 1 ) \frac{x ^{3} + x ^{2} - 10 x + 8}{x - 1}}{x - 2}

\frac{x ^{3} + x ^{2} - 10 x + 8}{x - 1} = x^{2} + 2 x - 8

= \frac{( x - 1 ) ( x ^{2} + 2 x - 8 )}{x - 2}

Factor

x^{2} + 2 x - 8 : (x - 2) (x + 4)

= \frac{( x - 1 ) ( x - 2 ) ( x + 4 )}{x - 2}

Cancel the common factor:

x - 2

= (x - 1) (x + 4)

(x - 1) (x + 1)^{2}

- 6 \div 3

(d^{2} + 6 d + 9) - (d^{3} + 6 d + 9)

\frac{48}{8}

What is ((x^3+x^2-10x+8))/((x-2)) ?
The solution to ((x^3+x^2-10x+8))/((x-2)) is (x-1)(x+4)