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Popular >

expand (x^2+1)^4

Solution

expand

(x^{2} + 1)^{4}

Solution

x^{8} + 4 x^{6} + 6 x^{4} + 4 x^{2} + 1

Solution steps

(x^{2} + 1)^{4}

Apply binomial theorem:

(a + b)^{n} = i = 0 \sum n (i n) a^{(n - i)} b^{i}

a = x^{2}, b = 1

= i = 0 \sum 4 (i 4) (x^{2})^{(4 - i)} \cdot 1^{i}

Expand summation

= \frac{4 !}{0 ! ( 4 - 0 ) !} (x^{2})^{4} \cdot 1^{0} + \frac{4 !}{1 ! ( 4 - 1 ) !} (x^{2})^{3} \cdot 1^{1} + \frac{4 !}{2 ! ( 4 - 2 ) !} (x^{2})^{2} \cdot 1^{2} + \frac{4 !}{3 ! ( 4 - 3 ) !} (x^{2})^{1} \cdot 1^{3} + \frac{4 !}{4 ! ( 4 - 4 ) !} (x^{2})^{0} \cdot 1^{4}

Simplify

\frac{4 !}{0 ! ( 4 - 0 ) !} (x^{2})^{4} \cdot 1^{0} : x^{8}

Simplify

\frac{4 !}{1 ! ( 4 - 1 ) !} (x^{2})^{3} \cdot 1^{1} : 4 x^{6}

Simplify

\frac{4 !}{2 ! ( 4 - 2 ) !} (x^{2})^{2} \cdot 1^{2} : 6 x^{4}

Simplify

\frac{4 !}{3 ! ( 4 - 3 ) !} (x^{2})^{1} \cdot 1^{3} : 4 x^{2}

Simplify

\frac{4 !}{4 ! ( 4 - 4 ) !} (x^{2})^{0} \cdot 1^{4} : 1

= x^{8} + 4 x^{6} + 6 x^{4} + 4 x^{2} + 1

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Frequently Asked Questions (FAQ)

What is expand (x^2+1)^4 ?
The solution to expand (x^2+1)^4 is x^8+4x^6+6x^4+4x^2+1