What are the solutions to the equation r^2-8r+14=0 ?

The solutions to the equation r^2-8r+14=0 are r=4+sqrt(2),r=4-sqrt(2)

Find the zeros of r^2-8r+14=0

The zeros of r^2-8r+14=0 are r=4+sqrt(2),r=4-sqrt(2)

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r^{2} - 8 r + 14 = 0

r = 4 + 2, r = 4 - 2

Solution steps

r^{2} - 8 r + 14 = 0

Solve with the quadratic formula

r_{1, 2} = \frac{- ( - 8 ) \pm ( - 8 ) ^{2} - 4 \cdot 1 \cdot 14}{2 \cdot 1}

(- 8)^{2} - 4 \cdot 1 \cdot 14 = 22

r_{1, 2} = \frac{- ( - 8 ) \pm 2 2}{2 \cdot 1}

Separate the solutions

r_{1} = \frac{- ( - 8 ) + 2 2}{2 \cdot 1}, r_{2} = \frac{- ( - 8 ) - 2 2}{2 \cdot 1}

r = \frac{- ( - 8 ) + 2 2}{2 \cdot 1} : 4 + 2

r = \frac{- ( - 8 ) - 2 2}{2 \cdot 1} : 4 - 2

The solutions to the quadratic equation are:

r = 4 + 2, r = 4 - 2

t^{2} + 6 t - 16 = 0

\frac{3 x - 5}{7} = - 8 x + 33

\frac{1}{2} x^{2} + 23 = 28

0^{1}

- 2 (w + 4) + 9 < - 11

What are the solutions to the equation r^2-8r+14=0 ?
The solutions to the equation r^2-8r+14=0 are r=4+sqrt(2),r=4-sqrt(2)
Find the zeros of r^2-8r+14=0
The zeros of r^2-8r+14=0 are r=4+sqrt(2),r=4-sqrt(2)