What is (7m+42)/(m^2+3m-18) ?

The solution to (7m+42)/(m^2+3m-18) is 7/(m-3)

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simplify (7m+42)/(m^2+3m-18)

simplify

\frac{7 m + 42}{m ^{2} + 3 m - 18}

\frac{7}{m - 3}

Solution steps

\frac{7 m + 42}{m ^{2} + 3 m - 18}

Factor

7 m + 42 : 7 (m + 6)

= \frac{7 ( m + 6 )}{m ^{2} + 3 m - 18}

Factor

m^{2} + 3 m - 18 : (m - 3) (m + 6)

= \frac{7 ( m + 6 )}{( m - 3 ) ( m + 6 )}

Cancel the common factor:

m + 6

= \frac{7}{m - 3}

11 \times 11

\frac{2}{9}

\frac{9}{24}

\frac{y ^{2}}{y}

(- 9 x^{2} - 2 x) - (- 9 x^{2} - 3 x)