What are the solutions to the equation 8k^2-8=120 ?

The solutions to the equation 8k^2-8=120 are k=4,k=-4

Find the zeros of 8k^2-8=120

The zeros of 8k^2-8=120 are k=4,k=-4

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8 k^{2} - 8 = 120

k = 4, k = - 4

Solution steps

8 k^{2} - 8 = 120

Move

8

to the right side

8 k^{2} = 128

Divide both sides by

8

k^{2} = 16

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

k = 16, k = - 16

16 = 4

- 16 = - 4

k = 4, k = - 4

p^{2} - 8 p + 7

23 < f + 12

- 8 (x + 5) = - 8 x - 5 (x + 8)

(3 x^{2} - 6 x + 9)^{3}

1 - 5 x + 3 x^{2} = x^{2}

What are the solutions to the equation 8k^2-8=120 ?
The solutions to the equation 8k^2-8=120 are k=4,k=-4
Find the zeros of 8k^2-8=120
The zeros of 8k^2-8=120 are k=4,k=-4