What is 2-5*2+(6^2)/(sqrt(9(-2)^3)) ?

The solution to 2-5*2+(6^2)/(sqrt(9(-2)^3)) is (3sqrt(2))/i-8

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simplify 2-5*2+(6^2)/(sqrt(9(-2)^3))

simplify

2 - 5 \cdot 2 + \frac{6 ^{2}}{9 ( - 2 ) ^{3}}

\frac{3 2}{i} - 8

Solution steps

2 - 5 \cdot 2 + \frac{6 ^{2}}{9 ( - 2 ) ^{3}}

5 \cdot 2 = 10

\frac{6 ^{2}}{9 ( - 2 ) ^{3}} = \frac{3 2}{i}

= 2 - 10 + \frac{3 2}{i}

Subtract the numbers:

2 - 10 = - 8

= \frac{3 2}{i} - 8

(8 x^{2} - 7 x - 2) - (6 x^{2} - x + 3)

(- 8 x^{2} + 10 x + 4) - (- 4 x + 10)

(10 x^{2} + 3 x + 9) + (5 x^{2} + x + 4)

(x - 2)^{2} - 1

(x + 3) (x - 4)

What is 2-5*2+(6^2)/(sqrt(9(-2)^3)) ?
The solution to 2-5*2+(6^2)/(sqrt(9(-2)^3)) is (3sqrt(2))/i-8