What is (x^2-9)/(x^2-x-6) ?

The solution to (x^2-9)/(x^2-x-6) is (x+3)/(x+2)

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simplify (x^2-9)/(x^2-x-6)

simplify

\frac{x ^{2} - 9}{x ^{2} - x - 6}

\frac{x + 3}{x + 2}

Solution steps

\frac{x ^{2} - 9}{x ^{2} - x - 6}

Factor

x^{2} - 9 : (x + 3) (x - 3)

= \frac{( x + 3 ) ( x - 3 )}{x ^{2} - x - 6}

Factor

x^{2} - x - 6 : (x + 2) (x - 3)

= \frac{( x + 3 ) ( x - 3 )}{( x + 2 ) ( x - 3 )}

Cancel the common factor:

x - 3

= \frac{x + 3}{x + 2}

\frac{50}{75}

1^{x}

\frac{5}{x} - \frac{3 x + 2}{x + 1} + \frac{2}{x ^{2} + x}

8 \div \frac{1}{2}

(2 x^{2} + 7 x) + (- x^{2} + 10 x + 3)