What is (4/5)^3*(3/10)^{-2}*(1 1/3)^{-4} ?

The solution to (4/5)^3*(3/10)^{-2}*(1 1/3)^{-4} is 1 4/5

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simplify (4/5)^3(3/10)^{-2}(1 1/3)^{-4}

simplify

(\frac{4}{5})^{3} \cdot (\frac{3}{10})^{- 2} \cdot (1 \frac{1}{3})^{- 4}

1 \frac{4}{5}

Decimal Notation

1.8

Solution steps

(\frac{4}{5})^{3} \cdot (\frac{3}{10})^{- 2} \cdot (1 \frac{1}{3})^{- 4}

Convert mixed numbers to improper fractions:

1 \frac{1}{3} = \frac{4}{3}

= (\frac{4}{5})^{3} \cdot (\frac{3}{10})^{- 2} \cdot (\frac{4}{3})^{- 4}

(\frac{4}{5})^{3} = \frac{64}{125}

= \frac{64}{125} (\frac{3}{10})^{- 2} (\frac{4}{3})^{- 4}

(\frac{3}{10})^{- 2} = \frac{100}{9}

= \frac{64}{125} \cdot \frac{100}{9} (\frac{4}{3})^{- 4}

Apply exponent rule:

a^{- b} = \frac{1}{a ^{b}}

(\frac{4}{3})^{- 4} = \frac{1}{( \frac{4}{3} ) ^{4}}

= \frac{64}{125} \cdot \frac{100}{9} \cdot \frac{1}{( \frac{4}{3} ) ^{4}}

(\frac{4}{3})^{4} = \frac{256}{81}

= \frac{64}{125} \cdot \frac{100}{9} \cdot \frac{1}{\frac{256}{81}}

Apply the fraction rule:

\frac{1}{\frac{b}{c}} = \frac{c}{b}

= \frac{64}{125} \cdot \frac{100}{9} \cdot \frac{81}{256}

\frac{64}{125} \cdot \frac{100}{9} \cdot \frac{81}{256} = \frac{9}{5}

= \frac{9}{5}

Convert improper fractions to mixed numbers:

\frac{9}{5} = 1 \frac{4}{5}

= 1 \frac{4}{5}

\frac{x ^{3} - 8}{x ^{2} - 4}

4 - (- 6)

(x - 2)^{2} + 1

(\frac{a}{a ^{2}})^{- 2}

- 5 + (- 4)

What is (4/5)^3*(3/10)^{-2}*(1 1/3)^{-4} ?
The solution to (4/5)^3*(3/10)^{-2}*(1 1/3)^{-4} is 1 4/5