What is (4n^2+3n-5)-(2n^2+3n+6) ?

The solution to (4n^2+3n-5)-(2n^2+3n+6) is 2n^2-11

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simplify (4n^2+3n-5)-(2n^2+3n+6)

simplify

(4 n^{2} + 3 n - 5) - (2 n^{2} + 3 n + 6)

2 n^{2} - 11

Solution steps

(4 n^{2} + 3 n - 5) - (2 n^{2} + 3 n + 6)

Apply rule:

(a) = a

(4 n^{2} + 3 n - 5) = 4 n^{2} + 3 n - 5

= 4 n^{2} + 3 n - 5 - (2 n^{2} + 3 n + 6)

Apply the distributive law:

- (a + b) = - a - b

- (2 n^{2} + 3 n + 6) = - 2 n^{2} - 3 n - 6

= 4 n^{2} + 3 n - 5 - 2 n^{2} - 3 n - 6

Group like terms

= 4 n^{2} - 2 n^{2} + 3 n - 3 n - 5 - 6

Add similar elements:

4 n^{2} - 2 n^{2} = 2 n^{2}

= 2 n^{2} + 3 n - 3 n - 5 - 6

Add similar elements:

3 n - 3 n = 0

= 2 n^{2} - 5 - 6

Subtract the numbers:

- 5 - 6 = - 11

= 2 n^{2} - 11

\frac{x ^{2} + 5 x + 6}{x + 3}

8.2

∣ - x ∣

(x^{2} - x)^{2}

(x^{2} + 3 x + 5) - (x^{2} + 3 x + 5)

What is (4n^2+3n-5)-(2n^2+3n+6) ?
The solution to (4n^2+3n-5)-(2n^2+3n+6) is 2n^2-11