What is (6/(k-4))/(\frac{k+6){k^2+2k-24}} ?

The solution to (6/(k-4))/(\frac{k+6){k^2+2k-24}} is 6

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simplify (6/(k-4))/(\frac{k+6){k^2+2k-24}}

simplify

\frac{\frac{6}{k - 4}}{\frac{k + 6}{k ^{2} + 2 k - 24}}

6

Solution steps

\frac{\frac{6}{k - 4}}{\frac{k + 6}{k ^{2} + 2 k - 24}}

Apply the fraction rule:

\frac{\frac{a}{b}}{\frac{c}{d}} = \frac{a \cdot d}{b \cdot c}

= \frac{6 ( k ^{2} + 2 k - 24 )}{( k - 4 ) ( k + 6 )}

Cancel

\frac{6 ( k ^{2} + 2 k - 24 )}{( k - 4 ) ( k + 6 )} : 6

= 6

(32 - 14)^{2}

(2 x + 4) (2 x - 4)

(8 r^{2} - 7 r - 9) + (- r^{2} + r)

(m - 4)^{2}

(x^{2} + 1) (x - 1)

What is (6/(k-4))/(\frac{k+6){k^2+2k-24}} ?
The solution to (6/(k-4))/(\frac{k+6){k^2+2k-24}} is 6