What is (6a^3-5a^2+8a-3)+(a^3-12a^2-4a+2) ?

The solution to (6a^3-5a^2+8a-3)+(a^3-12a^2-4a+2) is 7a^3-17a^2+4a-1

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simplify (6a^3-5a^2+8a-3)+(a^3-12a^2-4a+2)

simplify

(6 a^{3} - 5 a^{2} + 8 a - 3) + (a^{3} - 12 a^{2} - 4 a + 2)

7 a^{3} - 17 a^{2} + 4 a - 1

Solution steps

(6 a^{3} - 5 a^{2} + 8 a - 3) + (a^{3} - 12 a^{2} - 4 a + 2)

Simplify

(6 a^{3} - 5 a^{2} + 8 a - 3) + (a^{3} - 12 a^{2} - 4 a + 2) : 6 a^{3} - 5 a^{2} + 8 a - 3 + a^{3} - 12 a^{2} - 4 a + 2

= 6 a^{3} - 5 a^{2} + 8 a - 3 + a^{3} - 12 a^{2} - 4 a + 2

Group like terms

= 6 a^{3} + a^{3} - 5 a^{2} - 12 a^{2} + 8 a - 4 a - 3 + 2

Add similar elements:

6 a^{3} + a^{3} = 7 a^{3}

= 7 a^{3} - 5 a^{2} - 12 a^{2} + 8 a - 4 a - 3 + 2

Add similar elements:

- 5 a^{2} - 12 a^{2} = - 17 a^{2}

= 7 a^{3} - 17 a^{2} + 8 a - 4 a - 3 + 2

Add similar elements:

8 a - 4 a = 4 a

= 7 a^{3} - 17 a^{2} + 4 a - 3 + 2

Add the numbers:

- 3 + 2 = - 1

= 7 a^{3} - 17 a^{2} + 4 a - 1

lo g_{\frac{1}{6}} (4) + lo g_{\frac{1}{6}} (9)

\frac{5 y}{x} + \frac{3 x}{y}

35 \div 7

e^{2 l n (y)}

\frac{2 x + 1}{x - 5} + \frac{2}{x}

What is (6a^3-5a^2+8a-3)+(a^3-12a^2-4a+2) ?
The solution to (6a^3-5a^2+8a-3)+(a^3-12a^2-4a+2) is 7a^3-17a^2+4a-1