What is (8x^2-2x+1)-(3x^2+5x-8) ?

The solution to (8x^2-2x+1)-(3x^2+5x-8) is 5x^2-7x+9

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simplify (8x^2-2x+1)-(3x^2+5x-8)

simplify

(8 x^{2} - 2 x + 1) - (3 x^{2} + 5 x - 8)

5 x^{2} - 7 x + 9

Solution steps

(8 x^{2} - 2 x + 1) - (3 x^{2} + 5 x - 8)

Apply rule:

(a) = a

(8 x^{2} - 2 x + 1) = 8 x^{2} - 2 x + 1

= 8 x^{2} - 2 x + 1 - (3 x^{2} + 5 x - 8)

Apply the distributive law:

- (a + b) = - a - b

- (3 x^{2} + 5 x - 8) = - 3 x^{2} - 5 x + 8

= 8 x^{2} - 2 x + 1 - 3 x^{2} - 5 x + 8

Group like terms

= 8 x^{2} - 3 x^{2} - 2 x - 5 x + 1 + 8

Add similar elements:

8 x^{2} - 3 x^{2} = 5 x^{2}

= 5 x^{2} - 2 x - 5 x + 1 + 8

Add similar elements:

- 2 x - 5 x = - 7 x

= 5 x^{2} - 7 x + 1 + 8

Add the numbers:

1 + 8 = 9

= 5 x^{2} - 7 x + 9

(- 2 - 6 i) - (- 2 - 4 i)

lo g_{\frac{2}{5}} (\frac{125}{8})

\frac{2}{3}

\frac{m ^{2} - n ^{2}}{( m + n ) ^{2}}

\frac{5 x}{2}

What is (8x^2-2x+1)-(3x^2+5x-8) ?
The solution to (8x^2-2x+1)-(3x^2+5x-8) is 5x^2-7x+9