What is expand (a^{x+1}-2b^{x-1})(2b^{x-1}+a^{x+1}) ?

The solution to expand (a^{x+1}-2b^{x-1})(2b^{x-1}+a^{x+1}) is a^{2(x+1)}-(2b^{x-1})^2

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expand (a^{x+1}-2b^{x-1})(2b^{x-1}+a^{x+1})

expand

(a^{x + 1} - 2 b^{x - 1}) (2 b^{x - 1} + a^{x + 1})

a^{2 (x + 1)} - (2 b^{x - 1})^{2}

Solution steps

(a^{x + 1} - 2 b^{x - 1}) (2 b^{x - 1} + a^{x + 1})

Apply Difference of Two Squares

(a^{x + 1} - 2 b^{x - 1}) (2 b^{x - 1} + a^{x + 1}) : a^{2 (x + 1)} - (2 b^{x - 1})^{2}

= a^{2 (x + 1)} - (2 b^{x - 1})^{2}

\frac{4 x}{4}

3 (- 3)

\frac{1}{\frac{3}{2}}

1 \times \frac{1}{2}

108 a^{6}

What is expand (a^{x+1}-2b^{x-1})(2b^{x-1}+a^{x+1}) ?
The solution to expand (a^{x+1}-2b^{x-1})(2b^{x-1}+a^{x+1}) is a^{2(x+1)}-(2b^{x-1})^2