What is ((x^3yz^0)/(2x^5y^{-3)})^3 ?

The solution to ((x^3yz^0)/(2x^5y^{-3)})^3 is (y^{12})/(8x^6)

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simplify ((x^3yz^0)/(2x^5y^{-3)})^3

simplify

(\frac{x ^{3} y z ^{0}}{2 x ^{5} y ^{- 3}})^{3}

\frac{y ^{12}}{8 x ^{6}}

Solution steps

(\frac{x ^{3} y z ^{0}}{2 x ^{5} y ^{- 3}})^{3}

Apply exponent rule:

(\frac{a}{b})^{c} = \frac{a ^{c}}{b ^{c}}

= \frac{( x ^{3} y z ^{0} ) ^{3}}{( 2 x ^{5} y ^{- 3} ) ^{3}}

Simplify

(x^{3} y z^{0})^{3} : x^{9} y^{3}

= \frac{x ^{9} y ^{3}}{( 2 x ^{5} y ^{- 3} ) ^{3}}

Simplify

(2 x^{5} y^{- 3})^{3} : \frac{8 x ^{15}}{y ^{9}}

= \frac{x ^{9} y ^{3}}{\frac{8 x ^{15}}{y ^{9}}}

Apply the fraction rule:

\frac{a}{\frac{b}{c}} = \frac{a \cdot c}{b}

= \frac{x ^{9} y ^{3} y ^{9}}{8 x ^{15}}

Apply exponent rule:

\frac{x ^{a}}{x ^{b}} = \frac{1}{x ^{b - a}}

\frac{x ^{9}}{x ^{15}} = \frac{1}{x ^{15 - 9}}

= \frac{y ^{9} y ^{3}}{8 x ^{15 - 9}}

Subtract the numbers:

15 - 9 = 6

= \frac{y ^{9} y ^{3}}{8 x ^{6}}

y^{9} y^{3} = y^{12}

= \frac{y ^{12}}{8 x ^{6}}

lo g_{10} (lo g_{10} (1 0^{10000}))

5 \times 3

e^{l n (x + 1)}

(d^{2} + 3) (d^{2} + 2 d + 1)

4 \cdot (- 4)

What is ((x^3yz^0)/(2x^5y^{-3)})^3 ?
The solution to ((x^3yz^0)/(2x^5y^{-3)})^3 is (y^{12})/(8x^6)