What is (4-3i)/(-1-4i) ?

The solution to (4-3i)/(-1-4i) is 8/17+19/17 i

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simplify (4-3i)/(-1-4i)

simplify

\frac{4 - 3 i}{- 1 - 4 i}

\frac{8}{17} + \frac{19}{17} i

Solution steps

\frac{4 - 3 i}{- 1 - 4 i}

Multiply by the conjugate

\frac{- 1 + 4 i}{- 1 + 4 i}

= \frac{( 4 - 3 i ) ( - 1 + 4 i )}{( - 1 - 4 i ) ( - 1 + 4 i )}

Simplify

\frac{( 4 - 3 i ) ( - 1 + 4 i )}{( - 1 - 4 i ) ( - 1 + 4 i )} : \frac{8 + 19 i}{17}

= \frac{8 + 19 i}{17}

Rewrite in standard complex form:

\frac{8}{17} + \frac{19}{17} i

= \frac{8}{17} + \frac{19}{17} i

(- 7 x^{2} - 4 x - 1) - (6 x^{2} + 4 x)

\frac{x ^{2} - 1}{x ^{2} + 2 x + 1}

(b - 6) (b - 5)

\frac{20}{40}

\frac{3}{2} \div \frac{1}{2}