What is the answer to (x-2)(x+1)=x^2+4x ?

The answer to (x-2)(x+1)=x^2+4x is x=-2/5

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(x-2)(x+1)=x^2+4x

(x - 2) (x + 1) = x^{2} + 4 x

x = - \frac{2}{5}

Decimal Notation

x = - 0.4

Solution steps

(x - 2) (x + 1) = x^{2} + 4 x

Expand

(x - 2) (x + 1) : x^{2} - x - 2

x^{2} - x - 2 = x^{2} + 4 x

Move

2

to the right side

x^{2} - x = x^{2} + 4 x + 2

Subtract

x^{2} + 4 x

from both sides

x^{2} - x - (x^{2} + 4 x) = x^{2} + 4 x + 2 - (x^{2} + 4 x)

Simplify

- 5 x = 2

Divide both sides by

- 5

x = - \frac{2}{5}

15 - 2 x \geq x^{2}

\frac{5}{2} x + 7 = x + \frac{11}{2}

3 x = 48

\frac{x + 7}{x - 7} < 0

x^{2} + (0 - 8)^{2} = 64

What is the answer to (x-2)(x+1)=x^2+4x ?
The answer to (x-2)(x+1)=x^2+4x is x=-2/5
Solve for x: (x-2)(x+1)=x^2+4x
The solution is x=-2/5