What is (6a^3+7a^2)-(5a^3+9a^2+a) ?

The solution to (6a^3+7a^2)-(5a^3+9a^2+a) is a^3-2a^2-a

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simplify (6a^3+7a^2)-(5a^3+9a^2+a)

simplify

(6 a^{3} + 7 a^{2}) - (5 a^{3} + 9 a^{2} + a)

a^{3} - 2 a^{2} - a

Solution steps

(6 a^{3} + 7 a^{2}) - (5 a^{3} + 9 a^{2} + a)

Apply rule:

(a) = a

(6 a^{3} + 7 a^{2}) = 6 a^{3} + 7 a^{2}

= 6 a^{3} + 7 a^{2} - (5 a^{3} + 9 a^{2} + a)

Apply the distributive law:

- (a + b) = - a - b

- (5 a^{3} + 9 a^{2} + a) = - 5 a^{3} - 9 a^{2} - a

= 6 a^{3} + 7 a^{2} - 5 a^{3} - 9 a^{2} - a

Group like terms

= 6 a^{3} - 5 a^{3} + 7 a^{2} - 9 a^{2} - a

Add similar elements:

6 a^{3} - 5 a^{3} = a^{3}

= a^{3} + 7 a^{2} - 9 a^{2} - a

Add similar elements:

7 a^{2} - 9 a^{2} = - 2 a^{2}

= a^{3} - 2 a^{2} - a

(3 z^{5} + 7 z^{2})^{2}

\frac{1}{2} \div 1

\frac{1}{2} \div 5

- 4 + 12

(12 - 9 i)^{2}

What is (6a^3+7a^2)-(5a^3+9a^2+a) ?
The solution to (6a^3+7a^2)-(5a^3+9a^2+a) is a^3-2a^2-a