What is factor 2y^2+7y+3 ?

The solution to factor 2y^2+7y+3 is (2y+1)(y+3)

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factor 2y^2+7y+3

factor

2 y^{2} + 7 y + 3

(2 y + 1) (y + 3)

Solution steps

2 y^{2} + 7 y + 3

Break the expression into groups

= (2 y^{2} + y) + (6 y + 3)

Factor out

y

from

2 y^{2} + y : y (2 y + 1)

Factor out

3

from

6 y + 3 : 3 (2 y + 1)

= y (2 y + 1) + 3 (2 y + 1)

Factor out common term

2 y + 1

= (2 y + 1) (y + 3)

\frac{12}{2}

x^{2} = 6

\frac{1}{4} (4)^{1}

62 = 12 + b

14 r = - 9