What is (\frac{6x^2)/(11y^3)}{(9x^4)/(22y^2)} ?

The solution to (\frac{6x^2)/(11y^3)}{(9x^4)/(22y^2)} is 4/(3x^2y)

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simplify (\frac{6x^2)/(11y^3)}{(9x^4)/(22y^2)}

simplify

\frac{\frac{6 x ^{2}}{11 y ^{3}}}{\frac{9 x ^{4}}{22 y ^{2}}}

\frac{4}{3 x ^{2} y}

Solution steps

\frac{\frac{6 x ^{2}}{11 y ^{3}}}{\frac{9 x ^{4}}{22 y ^{2}}}

Apply the fraction rule:

\frac{\frac{a}{b}}{\frac{c}{d}} = \frac{a \cdot d}{b \cdot c}

= \frac{6 x ^{2} \cdot 22 y ^{2}}{11 y ^{3} \cdot 9 x ^{4}}

Cancel

\frac{6 x ^{2} \cdot 22 y ^{2}}{11 y ^{3} \cdot 9 x ^{4}} : \frac{4}{y \cdot 3 x ^{2}}

= \frac{4}{y \cdot 3 x ^{2}}

= \frac{4}{3 x ^{2} y}

(4 x + 3)^{3}

\frac{\frac{x}{2}}{2}

(x - 6) (x + 4)

(a + b - c)^{2}

lo g_{9} (18)

What is (\frac{6x^2)/(11y^3)}{(9x^4)/(22y^2)} ?
The solution to (\frac{6x^2)/(11y^3)}{(9x^4)/(22y^2)} is 4/(3x^2y)