What is the answer to 14-(5x-1)(2x+3)=17-(10x+1)(x-6) ?

The answer to 14-(5x-1)(2x+3)=17-(10x+1)(x-6) is x=-1/12

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14-(5x-1)(2x+3)=17-(10x+1)(x-6)

14 - (5 x - 1) (2 x + 3) = 17 - (10 x + 1) (x - 6)

x = - \frac{1}{12}

Decimal Notation

x = - 0.08333 \dots

Solution steps

14 - (5 x - 1) (2 x + 3) = 17 - (10 x + 1) (x - 6)

Expand

14 - (5 x - 1) (2 x + 3) : - 10 x^{2} - 13 x + 17

Expand

17 - (10 x + 1) (x - 6) : - 10 x^{2} + 59 x + 23

- 10 x^{2} - 13 x + 17 = - 10 x^{2} + 59 x + 23

Move

17

to the right side

- 10 x^{2} - 13 x = - 10 x^{2} + 59 x + 6

Subtract

- 10 x^{2} + 59 x

from both sides

- 10 x^{2} - 13 x - (- 10 x^{2} + 59 x) = - 10 x^{2} + 59 x + 6 - (- 10 x^{2} + 59 x)

Simplify

- 72 x = 6

Divide both sides by

- 72

x = - \frac{1}{12}

\frac{x}{p ^{2}} + \frac{y}{pq}

\frac{1 + 7 i}{1 + i}

96 = 4 (a + 10)

lo g_{4} (320) - lo g_{4} (5)

x^{2} - 2 x - 48 \leq 0

What is the answer to 14-(5x-1)(2x+3)=17-(10x+1)(x-6) ?
The answer to 14-(5x-1)(2x+3)=17-(10x+1)(x-6) is x=-1/12
Solve for x: 14-(5x-1)(2x+3)=17-(10x+1)(x-6)
The solution is x=-1/12