What are the solutions to the equation 230+20x-0.5x^2=0 ?

The solutions to the equation 230+20x-0.5x^2=0 are x=-2(sqrt(215)-10),x=2(10+sqrt(215))

Find the zeros of 230+20x-0.5x^2=0

The zeros of 230+20x-0.5x^2=0 are x=-2(sqrt(215)-10),x=2(10+sqrt(215))

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230 + 20 x - 0.5 x^{2} = 0

x = - 2 (215 - 10), x = 2 (10 + 215)

Decimal Notation

x = - 9.32575 \dots, x = 49.32575 \dots

Solution steps

230 + 20 x - 0.5 x^{2} = 0

Multiply both sides by

10

2300 + 200 x - 5 x^{2} = 0

Write in the standard form

a x^{2} + b x + c = 0

- 5 x^{2} + 200 x + 2300 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 200 \pm 20 0 ^{2} - 4 ( - 5 ) \cdot 2300}{2 ( - 5 )}

20 0^{2} - 4 (- 5) \cdot 2300 = 20215

x_{1, 2} = \frac{- 200 \pm 20 215}{2 ( - 5 )}

Separate the solutions

x_{1} = \frac{- 200 + 20 215}{2 ( - 5 )}, x_{2} = \frac{- 200 - 20 215}{2 ( - 5 )}

x = \frac{- 200 + 20 215}{2 ( - 5 )} : - 2 (215 - 10)

x = \frac{- 200 - 20 215}{2 ( - 5 )} : 2 (10 + 215)

The solutions to the quadratic equation are:

x = - 2 (215 - 10), x = 2 (10 + 215)

13 x^{2} - 5 x \leq 0

7 b = 49

2 p^{2} - 10 p + 11 = 0

0.5 = \frac{1}{16} (x^{2} - 4 x + 4)

15 x^{4} - 15 x^{2}

What are the solutions to the equation 230+20x-0.5x^2=0 ?
The solutions to the equation 230+20x-0.5x^2=0 are x=-2(sqrt(215)-10),x=2(10+sqrt(215))
Find the zeros of 230+20x-0.5x^2=0
The zeros of 230+20x-0.5x^2=0 are x=-2(sqrt(215)-10),x=2(10+sqrt(215))