What is (rcos(θ))^2+(rsin(θ))^2 ?

The solution to (rcos(θ))^2+(rsin(θ))^2 is r^2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

simplify (rcos(θ))^2+(rsin(θ))^2

simplify

(r cos (θ))^{2} + (r sin (θ))^{2}

r^{2}

Solution steps

(r cos (θ))^{2} + (r sin (θ))^{2}

Use the Pythagorean identity:

cos^{2} (x) + sin^{2} (x) = 1

= r^{2} \cdot 1

Factor

(r cos (θ))^{2} + (r sin (θ))^{2} : r^{2} (cos^{2} (θ) + sin^{2} (θ))

= r^{2} (cos^{2} (θ) + sin^{2} (θ))

= r^{2}

6 \div \frac{1}{3}

(x + 1) (2 x^{2} - 10 x - 9)

(5 - 2 i) (4 - i)

\frac{48}{12}

\frac{x ^{2} + 4 x - 21}{x ^{2} - 49} - \frac{8}{2 x - 14}

What is (rcos(θ))^2+(rsin(θ))^2 ?
The solution to (rcos(θ))^2+(rsin(θ))^2 is r^2