What are the solutions to the equation x^2+10x+34=0 ?

The solutions to the equation x^2+10x+34=0 are x=-5+3i,x=-5-3i

Find the zeros of x^2+10x+34=0

The zeros of x^2+10x+34=0 are x=-5+3i,x=-5-3i

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x^{2} + 10 x + 34 = 0

x = - 5 + 3 i, x = - 5 - 3 i

Solution steps

x^{2} + 10 x + 34 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 10 \pm 1 0 ^{2} - 4 \cdot 1 \cdot 34}{2 \cdot 1}

Simplify

1 0^{2} - 4 \cdot 1 \cdot 34 : 6 i

x_{1, 2} = \frac{- 10 \pm 6 i}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 10 + 6 i}{2 \cdot 1}, x_{2} = \frac{- 10 - 6 i}{2 \cdot 1}

x = \frac{- 10 + 6 i}{2 \cdot 1} : - 5 + 3 i

x = \frac{- 10 - 6 i}{2 \cdot 1} : - 5 - 3 i

The solutions to the quadratic equation are:

x = - 5 + 3 i, x = - 5 - 3 i

\frac{x}{2} = 8

d - 10 \geq - 3

\frac{x ^{3} y ^{3}}{b} - \frac{x ^{4} y ^{2}}{a}

∣ 7 r - 6 ∣ = ∣ 8 r + 2 ∣

20 x^{2} - 56 x + 15 = 0

What are the solutions to the equation x^2+10x+34=0 ?
The solutions to the equation x^2+10x+34=0 are x=-5+3i,x=-5-3i
Find the zeros of x^2+10x+34=0
The zeros of x^2+10x+34=0 are x=-5+3i,x=-5-3i