What is log_{2}(64)+log_{3}(9)-log_{5}(625) ?

The solution to log_{2}(64)+log_{3}(9)-log_{5}(625) is 4

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simplify log_{2}(64)+log_{3}(9)-log_{5}(625)

simplify

lo g_{2} (64) + lo g_{3} (9) - lo g_{5} (625)

4

Solution steps

lo g_{2} (64) + lo g_{3} (9) - lo g_{5} (625)

lo g_{2} (64) = 6

lo g_{3} (9) = 2

lo g_{5} (625) = 4

= 6 + 2 - 4

Add the numbers:

6 + 2 - 4 = 4

= 4

(x - 5) (x - 6)

(2 mn - 5 m n^{2} + 8 m^{2} n) - (10 mn + 6 m^{2} n - 3 m n^{2} + mn)

\frac{1}{x + 1} + \frac{1}{x - 1}

- \frac{1}{2} \times 2

(4 - x^{2})^{3}

What is log_{2}(64)+log_{3}(9)-log_{5}(625) ?
The solution to log_{2}(64)+log_{3}(9)-log_{5}(625) is 4