What is (3a^2+1)-(4+2a^2) ?

The solution to (3a^2+1)-(4+2a^2) is a^2-3

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simplify (3a^2+1)-(4+2a^2)

simplify

(3 a^{2} + 1) - (4 + 2 a^{2})

a^{2} - 3

Solution steps

(3 a^{2} + 1) - (4 + 2 a^{2})

Apply rule:

(a) = a

(3 a^{2} + 1) = 3 a^{2} + 1

= 3 a^{2} + 1 - (4 + 2 a^{2})

Apply the distributive law:

- (a + b) = - a - b

- (4 + 2 a^{2}) = - 4 - 2 a^{2}

= 3 a^{2} + 1 - 4 - 2 a^{2}

Group like terms

= 3 a^{2} - 2 a^{2} + 1 - 4

Add similar elements:

3 a^{2} - 2 a^{2} = a^{2}

= a^{2} + 1 - 4

Subtract the numbers:

1 - 4 = - 3

= a^{2} - 3

2 \times \frac{1}{4}

\frac{2 6}{3}

lo g_{10} (x^{3})

6 \frac{3}{4}