What is expand (-4x-3)(2x^2-3x+4) ?

The solution to expand (-4x-3)(2x^2-3x+4) is -8x^3+6x^2-7x-12

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expand (-4x-3)(2x^2-3x+4)

expand

(- 4 x - 3) (2 x^{2} - 3 x + 4)

- 8 x^{3} + 6 x^{2} - 7 x - 12

Solution steps

(- 4 x - 3) (2 x^{2} - 3 x + 4)

Distribute parentheses

= - 4 x \cdot 2 x^{2} - 4 x (- 3 x) - 4 x \cdot 4 - 3 \cdot 2 x^{2} - 3 (- 3 x) - 3 \cdot 4

Simplify

- 4 x \cdot 2 x^{2} - 4 x (- 3 x) - 4 x \cdot 4 - 3 \cdot 2 x^{2} - 3 (- 3 x) - 3 \cdot 4 : - 8 x^{3} + 6 x^{2} - 7 x - 12

= - 8 x^{3} + 6 x^{2} - 7 x - 12

\frac{4 2 ^{642}}{22}

\frac{15}{21}

\frac{28}{36}

- 2 \frac{1}{2}

(x + a)^{3}

What is expand (-4x-3)(2x^2-3x+4) ?
The solution to expand (-4x-3)(2x^2-3x+4) is -8x^3+6x^2-7x-12