What is factor 2x^5+2x^4-6x^3-2x^2+4x ?

The solution to factor 2x^5+2x^4-6x^3-2x^2+4x is 2x(x-1)^2(x+2)(x+1)

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factor 2x^5+2x^4-6x^3-2x^2+4x

factor

2 x^{5} + 2 x^{4} - 6 x^{3} - 2 x^{2} + 4 x

2 x (x - 1)^{2} (x + 2) (x + 1)

Solution steps

2 x^{5} + 2 x^{4} - 6 x^{3} - 2 x^{2} + 4 x

Factor out common term

2 x : 2 x (x^{4} + x^{3} - 3 x^{2} - x + 2)

= 2 x (x^{4} + x^{3} - 3 x^{2} - x + 2)

Factor

x^{4} + x^{3} - 3 x^{2} - x + 2 : (x - 1) (x + 2) (x + 1) (x - 1)

= 2 x (x - 1) (x + 2) (x + 1) (x - 1)

Apply exponent rule:

aa = a^{2}

(x - 1) (x - 1) = (x - 1)^{2}

= 2 x (x - 1)^{2} (x + 2) (x + 1)

75 x^{3}

(m - 4)^{3}

(\frac{8}{27})^{- \frac{1}{3}}

x - 6 x

2 (x - 4)^{2}

What is factor 2x^5+2x^4-6x^3-2x^2+4x ?
The solution to factor 2x^5+2x^4-6x^3-2x^2+4x is 2x(x-1)^2(x+2)(x+1)