What are the solutions to the equation 0=x^2-2x-24 ?

The solutions to the equation 0=x^2-2x-24 are x=6,x=-4

Find the zeros of 0=x^2-2x-24

The zeros of 0=x^2-2x-24 are x=6,x=-4

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0 = x^{2} - 2 x - 24

x = 6, x = - 4

Solution steps

0 = x^{2} - 2 x - 24

Switch sides

x^{2} - 2 x - 24 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 2 ) \pm ( - 2 ) ^{2} - 4 \cdot 1 \cdot ( - 24 )}{2 \cdot 1}

(- 2)^{2} - 4 \cdot 1 \cdot (- 24) = 10

x_{1, 2} = \frac{- ( - 2 ) \pm 10}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 2 ) + 10}{2 \cdot 1}, x_{2} = \frac{- ( - 2 ) - 10}{2 \cdot 1}

x = \frac{- ( - 2 ) + 10}{2 \cdot 1} : 6

x = \frac{- ( - 2 ) - 10}{2 \cdot 1} : - 4

The solutions to the quadratic equation are:

x = 6, x = - 4

∣ x + 1 ∣ = ∣ x - 5 ∣

48 \cdot 3

\frac{3 a}{2 a + 6} - \frac{a - 1}{a + 3}

36 x^{2} - 169 y^{2}

4^{2} + 6

What are the solutions to the equation 0=x^2-2x-24 ?
The solutions to the equation 0=x^2-2x-24 are x=6,x=-4
Find the zeros of 0=x^2-2x-24
The zeros of 0=x^2-2x-24 are x=6,x=-4