What is ((2x^3)/(3x^2))^{-1} ?

The solution to ((2x^3)/(3x^2))^{-1} is 3/(2x)

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simplify ((2x^3)/(3x^2))^{-1}

simplify

(\frac{2 x ^{3}}{3 x ^{2}})^{- 1}

\frac{3}{2 x}

Solution steps

(\frac{2 x ^{3}}{3 x ^{2}})^{- 1}

Apply exponent rule:

a^{- 1} = \frac{1}{a}

(\frac{2 x ^{3}}{3 x ^{2}})^{- 1} = \frac{1}{\frac{2 x ^{3}}{3 x ^{2}}}

= \frac{1}{\frac{2 x ^{3}}{3 x ^{2}}}

Apply the fraction rule:

\frac{1}{\frac{b}{c}} = \frac{c}{b}

= \frac{3 x ^{2}}{2 x ^{3}}

Apply exponent rule:

\frac{x ^{a}}{x ^{b}} = \frac{1}{x ^{b - a}}

\frac{x ^{2}}{x ^{3}} = \frac{1}{x ^{3 - 2}}

= \frac{3}{2 x ^{3 - 2}}

Subtract the numbers:

3 - 2 = 1

= \frac{3}{2 x}

28 + a^{2} - 11 a

5 - - 25

lo g_{3} (3^{7})

(p - q)^{3}

56 \div 8