What are the solutions to the equation 60-60x=(8x+4)(x-1) ?

The solutions to the equation 60-60x=(8x+4)(x-1) are x=1,x=-8

Find the zeros of 60-60x=(8x+4)(x-1)

The zeros of 60-60x=(8x+4)(x-1) are x=1,x=-8

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60 - 60 x = (8 x + 4) (x - 1)

x = 1, x = - 8

Solution steps

60 - 60 x = (8 x + 4) (x - 1)

Expand

(8 x + 4) (x - 1) : 8 x^{2} - 4 x - 4

60 - 60 x = 8 x^{2} - 4 x - 4

Switch sides

8 x^{2} - 4 x - 4 = 60 - 60 x

Move

60 x

to the left side

8 x^{2} + 56 x - 4 = 60

Move

60

to the left side

8 x^{2} + 56 x - 64 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 56 \pm 5 6 ^{2} - 4 \cdot 8 ( - 64 )}{2 \cdot 8}

5 6^{2} - 4 \cdot 8 (- 64) = 72

x_{1, 2} = \frac{- 56 \pm 72}{2 \cdot 8}

Separate the solutions

x_{1} = \frac{- 56 + 72}{2 \cdot 8}, x_{2} = \frac{- 56 - 72}{2 \cdot 8}

x = \frac{- 56 + 72}{2 \cdot 8} : 1

x = \frac{- 56 - 72}{2 \cdot 8} : - 8

The solutions to the quadratic equation are:

x = 1, x = - 8

- 10 \leq 5 + x < - 5

2 (3 - 7 x) + 3 x < 3 (5 + 2 x)

3^{2} + 8^{2} = c^{2}

2^{3} - 2

(- \frac{3}{4})^{5}

What are the solutions to the equation 60-60x=(8x+4)(x-1) ?
The solutions to the equation 60-60x=(8x+4)(x-1) are x=1,x=-8
Find the zeros of 60-60x=(8x+4)(x-1)
The zeros of 60-60x=(8x+4)(x-1) are x=1,x=-8