What is the answer to 1/4+(2z-(3z-1)/8)= 2/3 ((z+2)/6)-2z ?

The answer to 1/4+(2z-(3z-1)/8)= 2/3 ((z+2)/6)-2z is z=-1/23

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1/4+(2z-(3z-1)/8)= 2/3 ((z+2)/6)-2z

\frac{1}{4} + (2 z - \frac{3 z - 1}{8}) = \frac{2}{3} (\frac{z + 2}{6}) - 2 z

z = - \frac{1}{23}

Decimal Notation

z = - 0.04347 \dots

Solution steps

\frac{1}{4} + (2 z - \frac{3 z - 1}{8}) = \frac{2}{3} (\frac{z + 2}{6}) - 2 z

Move

\frac{1}{4}

to the right side

2 z - \frac{3 z - 1}{8} = - \frac{1}{4} + \frac{- 17 z + 2}{9}

Multiply by LCM

144 z - 9 (3 z - 1) = - 18 + 8 (- 17 z + 2)

Expand

- 9 (3 z - 1) : - 27 z + 9

144 z - 27 z + 9 = - 18 + 8 (- 17 z + 2)

Add similar elements:

144 z - 27 z = 117 z

117 z + 9 = - 18 + 8 (- 17 z + 2)

Expand

- 18 + 8 (- 17 z + 2) : - 136 z - 2

117 z + 9 = - 136 z - 2

Move

9

to the right side

117 z = - 136 z - 11

Move

136 z

to the left side

253 z = - 11

Divide both sides by

253

z = - \frac{1}{23}

\frac{3 x - 6}{9} = \frac{36}{5}

7 \cdot 8

n^{2} - 144

- 4 x - 2 (8 x + 1) = - (- 2 x - 10)

2 (4 z - 1) = 3 (z + 2)

What is the answer to 1/4+(2z-(3z-1)/8)= 2/3 ((z+2)/6)-2z ?
The answer to 1/4+(2z-(3z-1)/8)= 2/3 ((z+2)/6)-2z is z=-1/23
Solve for z: 1/4+(2z-(3z-1)/8)= 2/3 ((z+2)/6)-2z
The solution is z=-1/23