simplify (-1+8i)^2

Solution

simplify

(- 1 + 8 i)^{2}

- 63 - 16 i

Solution steps

(- 1 + 8 i)^{2}

Apply Perfect Square Formula:

(a + b)^{2} = a^{2} + 2 ab + b^{2}

(- 1 + 8 i)^{2} = (- 1)^{2} + 2 (- 1) \cdot 8 i + (8 i)^{2}

= (- 1)^{2} + 2 (- 1) \cdot 8 i + (8 i)^{2}

Simplify

(- 1)^{2} + 2 (- 1) \cdot 8 i + (8 i)^{2} : - 16 i - 63

= - 16 i - 63

Rewrite in standard complex form:

- 63 - 16 i

= - 63 - 16 i

(1 + 2 x)^{3}

lo g_{10} (0.25)

\frac{7 x}{x y + 7 x + 7} + \frac{y}{yz + y + 7} + \frac{z}{x z + z + 1}

- 4^{- 1}

(7 + 2 i) - (- 3 - 3 i)