What are the solutions to the equation 4x^2+7x-1=0 ?

The solutions to the equation 4x^2+7x-1=0 are x=(-7+sqrt(65))/8 ,x=(-7-sqrt(65))/8

Find the zeros of 4x^2+7x-1=0

The zeros of 4x^2+7x-1=0 are x=(-7+sqrt(65))/8 ,x=(-7-sqrt(65))/8

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4 x^{2} + 7 x - 1 = 0

x = \frac{- 7 + 65}{8}, x = \frac{- 7 - 65}{8}

Decimal Notation

x = 0.13278 \dots, x = - 1.88278 \dots

Solution steps

4 x^{2} + 7 x - 1 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 7 \pm 7 ^{2} - 4 \cdot 4 ( - 1 )}{2 \cdot 4}

7^{2} - 4 \cdot 4 (- 1) = 65

x_{1, 2} = \frac{- 7 \pm 65}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- 7 + 65}{2 \cdot 4}, x_{2} = \frac{- 7 - 65}{2 \cdot 4}

x = \frac{- 7 + 65}{2 \cdot 4} : \frac{- 7 + 65}{8}

x = \frac{- 7 - 65}{2 \cdot 4} : \frac{- 7 - 65}{8}

The solutions to the quadratic equation are:

x = \frac{- 7 + 65}{8}, x = \frac{- 7 - 65}{8}

3 - \frac{4}{3}

49 y^{2} - 36

x^{3} - x^{2} - 90 x > 0

\frac{5}{4} \cdot 2

x - \frac{2}{7} = 8

What are the solutions to the equation 4x^2+7x-1=0 ?
The solutions to the equation 4x^2+7x-1=0 are x=(-7+sqrt(65))/8 ,x=(-7-sqrt(65))/8
Find the zeros of 4x^2+7x-1=0
The zeros of 4x^2+7x-1=0 are x=(-7+sqrt(65))/8 ,x=(-7-sqrt(65))/8