What is ((6m^2np^{-1})/(-3p^2r^{-2)})^4 ?

The solution to ((6m^2np^{-1})/(-3p^2r^{-2)})^4 is (16m^8n^4r^8)/(p^{12)}

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simplify ((6m^2np^{-1})/(-3p^2r^{-2)})^4

simplify

(\frac{6 m ^{2} n p ^{- 1}}{- 3 p ^{2} r ^{- 2}})^{4}

\frac{16 m ^{8} n ^{4} r ^{8}}{p ^{12}}

Solution steps

(\frac{6 m ^{2} n p ^{- 1}}{- 3 p ^{2} r ^{- 2}})^{4}

Apply exponent rule:

(\frac{a}{b})^{c} = \frac{a ^{c}}{b ^{c}}

= \frac{( 6 m ^{2} n p ^{- 1} ) ^{4}}{( - 3 p ^{2} r ^{- 2} ) ^{4}}

Simplify

(6 m^{2} n p^{- 1})^{4} : \frac{1296 m ^{8} n ^{4}}{p ^{4}}

= \frac{\frac{1296 m ^{8} n ^{4}}{p ^{4}}}{( - 3 p ^{2} r ^{- 2} ) ^{4}}

Simplify

(- 3 p^{2} r^{- 2})^{4} : \frac{81 p ^{8}}{r ^{8}}

= \frac{\frac{1296 m ^{8} n ^{4}}{p ^{4}}}{\frac{81 p ^{8}}{r ^{8}}}

Divide fractions:

\frac{\frac{a}{b}}{\frac{c}{d}} = \frac{a \cdot d}{b \cdot c}

= \frac{1296 m ^{8} n ^{4} r ^{8}}{p ^{4} \cdot 81 p ^{8}}

Divide the numbers:

\frac{1296}{81} = 16

= \frac{16 m ^{8} n ^{4} r ^{8}}{p ^{8} p ^{4}}

p^{8} p^{4} = p^{12}

= \frac{16 m ^{8} n ^{4} r ^{8}}{p ^{12}}

(3 - y)^{2}

x^{3} + \frac{1}{x ^{3}}

(\frac{1}{2} - b)^{2}

(4 t^{3} - 5)^{2}

(4 x + 5) (4 x - 5)

What is ((6m^2np^{-1})/(-3p^2r^{-2)})^4 ?
The solution to ((6m^2np^{-1})/(-3p^2r^{-2)})^4 is (16m^8n^4r^8)/(p^{12)}