What is (2+4i)+(4-i) ?

The solution to (2+4i)+(4-i) is 6+3i

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simplify (2+4i)+(4-i)

simplify

(2 + 4 i) + (4 - i)

6 + 3 i

Solution steps

(2 + 4 i) + (4 - i)

Group the real part and the imaginary part of the complex number

(a + bi) + (c + d i) = (a + c) + (b + d) i

= (2 + 4) + (4 - 1) i

Simplify

(2 + 4) + (4 - 1) i : 6 + 3 i

= 6 + 3 i

i^{97}

\frac{x ^{2} - 11 x + 18}{x ^{2} + 2 x - 8}

15 y^{2} + 16 y - 15

\frac{tan ^{2} ( x )}{sec ( x ) + 1} + 1

\frac{4 + 4 i}{- 2 - 8 i}