What is the answer to 2-(x+3)-(6-x+2)=2x-1 ?

The answer to 2-(x+3)-(6-x+2)=2x-1 is x=-4

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2-(x+3)-(6-x+2)=2x-1

2 - (x + 3) - (6 - x + 2) = 2 x - 1

x = - 4

Solution steps

2 - (x + 3) - (6 - x + 2) = 2 x - 1

Simplify

6 - x + 2 : - x + 8

2 - (x + 3) - (- x + 8) = 2 x - 1

Expand

2 - (x + 3) - (- x + 8) : - 9

- 9 = 2 x - 1

Move

9

to the right side

0 = 2 x + 8

Move

0

to the right side

= 2 x + 8

Move

2 x

to the left side

- 2 x = 8

Divide both sides by

- 2

x = - 4

0.5 d - 3 d + 5 = 0

x + 7 > 5

(\frac{n ^{\frac{2}{3}}}{m ^{\frac{4}{3}}})^{\frac{1}{2}}

\frac{5}{16 x ^{3} y ^{2}} + \frac{5}{6 x ^{2} y}

(2 a^{2} b^{3} c)^{4}

What is the answer to 2-(x+3)-(6-x+2)=2x-1 ?
The answer to 2-(x+3)-(6-x+2)=2x-1 is x=-4
Solve for x: 2-(x+3)-(6-x+2)=2x-1
The solution is x=-4