What is (x^3+8x^2)/(x^2+x-56)*(x^2-11x+28)/(4x) ?

The solution to (x^3+8x^2)/(x^2+x-56)*(x^2-11x+28)/(4x) is (x(x-4))/4

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simplify (x^3+8x^2)/(x^2+x-56)*(x^2-11x+28)/(4x)

simplify

\frac{x ^{3} + 8 x ^{2}}{x ^{2} + x - 56} \cdot \frac{x ^{2} - 11 x + 28}{4 x}

\frac{x ( x - 4 )}{4}

Solution steps

\frac{x ^{3} + 8 x ^{2}}{x ^{2} + x - 56} \cdot \frac{x ^{2} - 11 x + 28}{4 x}

Cancel

\frac{x ^{3} + 8 x ^{2}}{x ^{2} + x - 56} : \frac{x ^{2}}{x - 7}

= \frac{x ^{2}}{x - 7} \cdot \frac{x ^{2} - 11 x + 28}{4 x}

Apply the fraction rule:

\frac{a}{b} \cdot \frac{c}{d} = \frac{a \cdot c}{b \cdot d}

= \frac{x ^{2} ( x ^{2} - 11 x + 28 )}{( x - 7 ) \cdot 4 x}

Apply exponent rule:

a^{b + c} = a^{b} \cdot a^{c}

x^{2} = xx

= \frac{xx ( x ^{2} - 11 x + 28 )}{( x - 7 ) \cdot 4 x}

Cancel the common factor:

x

= \frac{x ( x ^{2} - 11 x + 28 )}{( x - 7 ) \cdot 4}

Factor

x^{2} - 11 x + 28 : (x - 4) (x - 7)

= \frac{x ( x - 4 ) ( x - 7 )}{( x - 7 ) \cdot 4}

Cancel the common factor:

x - 7

= \frac{x ( x - 4 )}{4}

- 9 - (- 3)

(3 x - 4)^{3}

(- 6 - i) - (7 + 10 i)

1 0^{2} + 1 0^{2}

11 x + 9 - 7

What is (x^3+8x^2)/(x^2+x-56)*(x^2-11x+28)/(4x) ?
The solution to (x^3+8x^2)/(x^2+x-56)*(x^2-11x+28)/(4x) is (x(x-4))/4