What is ((16x^3-8x^2+4x))/(2x) ?

The solution to ((16x^3-8x^2+4x))/(2x) is 8x^2-4x+2

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simplify ((16x^3-8x^2+4x))/(2x)

simplify

\frac{( 16 x ^{3} - 8 x ^{2} + 4 x )}{2 x}

8 x^{2} - 4 x + 2

Solution steps

\frac{16 x ^{3} - 8 x ^{2} + 4 x}{2 x}

Factor

16 x^{3} - 8 x^{2} + 4 x : 4 x (4 x^{2} - 2 x + 1)

= \frac{4 x ( 4 x ^{2} - 2 x + 1 )}{2 x}

Cancel the common factor:

x

= \frac{4 ( 4 x ^{2} - 2 x + 1 )}{2}

Divide the numbers:

\frac{4}{2} = 2

= 2 (4 x^{2} - 2 x + 1)

Expand

2 (4 x^{2} - 2 x + 1) : 8 x^{2} - 4 x + 2

= 8 x^{2} - 4 x + 2

\frac{cos ( x )}{sin ( x )} + \frac{sin ( x )}{cos ( x )}

- \frac{9}{- 3}

\frac{25}{20}

(3 - 2 i) (- 10 - 7 i)

b^{2}

What is ((16x^3-8x^2+4x))/(2x) ?
The solution to ((16x^3-8x^2+4x))/(2x) is 8x^2-4x+2