What are the solutions to the equation u^2-3u-28=0 ?

The solutions to the equation u^2-3u-28=0 are u=7,u=-4

Find the zeros of u^2-3u-28=0

The zeros of u^2-3u-28=0 are u=7,u=-4

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u^{2} - 3 u - 28 = 0

u = 7, u = - 4

Solution steps

u^{2} - 3 u - 28 = 0

Solve with the quadratic formula

u_{1, 2} = \frac{- ( - 3 ) \pm ( - 3 ) ^{2} - 4 \cdot 1 \cdot ( - 28 )}{2 \cdot 1}

(- 3)^{2} - 4 \cdot 1 \cdot (- 28) = 11

u_{1, 2} = \frac{- ( - 3 ) \pm 11}{2 \cdot 1}

Separate the solutions

u_{1} = \frac{- ( - 3 ) + 11}{2 \cdot 1}, u_{2} = \frac{- ( - 3 ) - 11}{2 \cdot 1}

u = \frac{- ( - 3 ) + 11}{2 \cdot 1} : 7

u = \frac{- ( - 3 ) - 11}{2 \cdot 1} : - 4

The solutions to the quadratic equation are:

u = 7, u = - 4

(\frac{3}{2})^{- 2} \cdot \frac{9}{16}

49 x^{2} y^{4}

k = - 2.03 \frac{- 1.05}{75}

3 x^{2} + 0.6 x = 16.8

3 x^{2} - x = - 4 x + 60

What are the solutions to the equation u^2-3u-28=0 ?
The solutions to the equation u^2-3u-28=0 are u=7,u=-4
Find the zeros of u^2-3u-28=0
The zeros of u^2-3u-28=0 are u=7,u=-4