What is (x^3-x^2-42x)/(2x^2-20x+42) ?

The solution to (x^3-x^2-42x)/(2x^2-20x+42) is (x(x+6))/(2(x-3))

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simplify (x^3-x^2-42x)/(2x^2-20x+42)

simplify

\frac{x ^{3} - x ^{2} - 42 x}{2 x ^{2} - 20 x + 42}

\frac{x ( x + 6 )}{2 ( x - 3 )}

Solution steps

\frac{x ^{3} - x ^{2} - 42 x}{2 x ^{2} - 20 x + 42}

Factor

x^{3} - x^{2} - 42 x : x (x + 6) (x - 7)

= \frac{x ( x + 6 ) ( x - 7 )}{2 x ^{2} - 20 x + 42}

Factor

2 x^{2} - 20 x + 42 : 2 (x - 3) (x - 7)

= \frac{x ( x + 6 ) ( x - 7 )}{2 ( x - 3 ) ( x - 7 )}

Cancel the common factor:

x - 7

= \frac{x ( x + 6 )}{2 ( x - 3 )}

a + a + a

(- 9 - 6 i) (11 - 7 i)

(2 a - 1) (2 a + 1)

lo g_{2} (lo g_{3} (8 1^{4}))

\frac{x + 2}{x ^{2} + x + 1} - \frac{1 - x ^{2}}{x ^{3} - 1}

What is (x^3-x^2-42x)/(2x^2-20x+42) ?
The solution to (x^3-x^2-42x)/(2x^2-20x+42) is (x(x+6))/(2(x-3))