What is (-2-4i)-(-5-2i)-(-5-5i) ?

The solution to (-2-4i)-(-5-2i)-(-5-5i) is 8+3i

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simplify (-2-4i)-(-5-2i)-(-5-5i)

simplify

(- 2 - 4 i) - (- 5 - 2 i) - (- 5 - 5 i)

8 + 3 i

Solution steps

(- 2 - 4 i) - (- 5 - 2 i) - (- 5 - 5 i)

Apply rule:

(a) = a

(- 2 - 4 i) = - 2 - 4 i

= - 2 - 4 i - (- 5 - 2 i) - (- 5 - 5 i)

Simplify

- 2 - 4 i - (- 5 - 2 i) - (- 5 - 5 i) : 3 i + 8

= 3 i + 8

Rewrite in standard complex form:

8 + 3 i

= 8 + 3 i

\frac{x ^{2} + 15 - 8 x}{3 - x}

(a + b) (a + b) (a + b)

- 3 (- 3)

(- 2 x - 3) (x^{2} - 5 x + 5)

\frac{39}{2}

What is (-2-4i)-(-5-2i)-(-5-5i) ?
The solution to (-2-4i)-(-5-2i)-(-5-5i) is 8+3i