What are the solutions to the equation v^2+10v+25=0 ?

The solutions to the equation v^2+10v+25=0 are v=-5

Find the zeros of v^2+10v+25=0

The zeros of v^2+10v+25=0 are v=-5

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v^{2} + 10 v + 25 = 0

v = - 5

Solution steps

v^{2} + 10 v + 25 = 0

Solve with the quadratic formula

v_{1, 2} = \frac{- 10 \pm 1 0 ^{2} - 4 \cdot 1 \cdot 25}{2 \cdot 1}

1 0^{2} - 4 \cdot 1 \cdot 25 = 0

v_{1, 2} = \frac{- 10 \pm 0}{2 \cdot 1}

v = \frac{- 10}{2 \cdot 1}

\frac{- 10}{2 \cdot 1} = - 5

v = - 5

The solution to the quadratic equation is:

v = - 5

- 16 t^{2} + 36 t - 20

216 y^{2}

x (2 x + 3) \geq 0

6 k^{2} - 7 k - 24

∣ 5 x - 1 ∣ < - 6

What are the solutions to the equation v^2+10v+25=0 ?
The solutions to the equation v^2+10v+25=0 are v=-5
Find the zeros of v^2+10v+25=0
The zeros of v^2+10v+25=0 are v=-5