What is (\frac{x^2-9)/(3x^2+8x-3)}{(x-3)/(x+2)} ?

The solution to (\frac{x^2-9)/(3x^2+8x-3)}{(x-3)/(x+2)} is (x+2)/(3x-1)

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simplify (\frac{x^2-9)/(3x^2+8x-3)}{(x-3)/(x+2)}

simplify

\frac{\frac{x ^{2} - 9}{3 x ^{2} + 8 x - 3}}{\frac{x - 3}{x + 2}}

\frac{x + 2}{3 x - 1}

Solution steps

\frac{\frac{x ^{2} - 9}{3 x ^{2} + 8 x - 3}}{\frac{x - 3}{x + 2}}

Apply the fraction rule:

\frac{\frac{a}{b}}{\frac{c}{d}} = \frac{a \cdot d}{b \cdot c}

= \frac{( x ^{2} - 9 ) ( x + 2 )}{( 3 x ^{2} + 8 x - 3 ) ( x - 3 )}

Cancel

\frac{( x ^{2} - 9 ) ( x + 2 )}{( 3 x ^{2} + 8 x - 3 ) ( x - 3 )} : \frac{x + 2}{3 x - 1}

= \frac{x + 2}{3 x - 1}

(x - 1)^{2} - 4

ln (ln (e^{e}))

1 + \frac{1}{x ^{2}}

(7 + 3 i) - (- 2 - 2 i)

What is (\frac{x^2-9)/(3x^2+8x-3)}{(x-3)/(x+2)} ?
The solution to (\frac{x^2-9)/(3x^2+8x-3)}{(x-3)/(x+2)} is (x+2)/(3x-1)